[20190416]exclusive latch测试脚本.txt

[20190416]exclusive latch测试脚本.txt

–//昨天做了shared latch的测试脚本,今天完善exclusive latch测试脚本,上个星期的测试我是手工执行的.
–//今天写一个脚本验证看看.相关链接:
http://blog.itpub.net/267265/viewspace-2641414/ => [20190415]关于shared latch(共享栓锁).txt
http://blog.itpub.net/267265/viewspace-2641497/ => [20190416]完善shared latch测试脚本2.txt

1.环境:
sys@book> @ ver1
port_string                    version        banner
—————————— ————– ——————————————————————————–
x86_64/linux 2.4.xx            11.2.0.4.0     oracle database 11g enterprise edition release 11.2.0.4.0 – 64bit production

$ cat peek.sh
#! /bib/bash
# 参数如下:latch_name monitoring_duration
sqlplus -s -l / as sysdba <<eof
col laddr new_value laddr
select sysdate,addr laddr from v\$latch_parent where name=’$1′;
oradebug setmypid
$(seq $2|xargs -i{} echo -e ‘oradebug peek 0x&laddr 8\nhost sleep 1’ )
eof

$ cat exclusive_latch.txt
/* 参数如下: @ latch.txt latch_name willing why where sleep_num */
connect / as sysdba
col laddr new_value laddr
select addr laddr from v$latch_parent where name=’&&1′;
oradebug setmypid
oradebug call kslgetl 0x&laddr &&2 &&3 &&4
host sleep &&5
oradebug call kslfre 0x&laddr
exit

$ cat latch_free.sql
/*
     this file is part of demos for “contemporary latch internals” seminar v.18.09.2010
     andrey s. nikolaev (andrey.nikolaev@rdtex.ru)
     http://andreynikolaev.wordpress.com

     this query shows trees of processes currently holding and waiting for latches
     tree output enumerates these processes and latches as following:
process <pid1>
 <latch1 holding by pid1>
    <processes waiting for latch1>
       …
 <latch2 holding by pid1>
    <processes waiting for latch2>
       …
process <pid2>

*/
set head off
set feedback off
set linesize 120
select sysdate from dual;
select   lpad(‘ ‘, (level – 1) )
     ||case when latch_holding is null then ‘process ‘||pid
             else ‘holding: ‘||latch_holding||’  “‘||name||'” lvl=’||level#||’ whr=’||whr||’ why=’||why ||’, sid=’||sid
       end
     || case when latch_waiting  is not  null then ‘, waiting for: ‘||latch_waiting||’ whr=’||whr||’ why=’||why
       end latchtree
 from (
/* latch holders */
select ksuprpid pid,ksuprlat latch_holding, null latch_waiting, to_char(ksuprpid) parent_id, rawtohex(ksuprlat) id,
       ksuprsid sid,ksuprllv level#,ksuprlnm name,ksuprlmd mode_,ksulawhy why,ksulawhr whr  from x$ksuprlat
union all
/* latch waiters */
select indx pid,null latch_holding, ksllawat latch_waiting,rawtohex(ksllawat) parent_id,to_char(indx) id,
       null,null,null,null,ksllawhy why,ksllawer whr from x$ksupr where ksllawat !=’00’
union all
/*  the roots of latch trees: processes holding latch but not waiting for latch */
select pid, null, null, null, to_char(pid),null,null,null,null,null,null from (
select distinct ksuprpid pid  from x$ksuprlat
minus
select indx pid from x$ksupr where ksllawat !=’00’)
) latch_op
connect by prior id=parent_id
start with parent_id  is null;

2.测试:
–//上个星期测试的是’test excl. parent2 l0′,继续拿它测试.
$ cat  x1.sh
#! /bin/bash
zdate=$(date ‘+%h%m%s’)
echo $zdate
source peek.sh ‘test excl. parent2 l0’ 20 | timestamp.pl >| /tmp/peekx_${zdate}.txt &
seq 20 | xargs -i{} echo -e ‘sqlplus -s -l / as sysdba <<< @latch_free\nsleep 1’  | bash >| /tmp/latch_freeo_${zdate}.txt &
# 参数如下: @ exclusive_latch.txt latch_name willing why where sleep_num
sqlplus /nolog @ exclusive_latch.txt ‘test excl. parent2 l0’ 1 2 3 6 > /dev/null &
sleep 2
sqlplus /nolog @ exclusive_latch.txt ‘test excl. parent2 l0’ 1 4 5 6 > /dev/null &
sleep 2
sqlplus /nolog @ exclusive_latch.txt ‘test excl. parent2 l0’ 1 6 7 6 > /dev/null &
wait

$ grep  -v ‘^.*: $’ /tmp/peekx_111121.txt | cut -c10- | uniq -c
      1  sysdate             laddr
      1  ——————- —————-
      1  2019-04-16 11:11:21 0000000060009978
      1  statement processed.
      6  [060009978, 060009980) = 00000023 00000000
      6  [060009978, 060009980) = 00000024 00000000
      6  [060009978, 060009980) = 00000025 00000000
      2  [060009978, 060009980) = 00000000 00000000

–//exclusive latch 是排他的,必须等其释放,其它进程才可以持有.
–//做一个测试,如果一个会话长时间持有已经死掉的情况下,oracle如何处理.

 $ cat x2.sh
#! /bin/bash
zdate=$(date ‘+%h%m%s’)
echo $zdate
source peek.sh ‘test excl. parent2 l0’ 320 | timestamp.pl >| /tmp/peekx_${zdate}.txt &
seq 320 | xargs -i{} echo -e ‘sqlplus -s -l / as sysdba <<< @latch_free\nsleep 1’  | bash >| /tmp/latch_free_${zdate}.txt &
# 参数如下: @ exclusive_latch.txt latch_name willing why where sleep_num
sqlplus /nolog @ exclusive_latch.txt ‘test excl. parent2 l0’ 1 2 3 300 > /dev/null &
sleep 2
sqlplus /nolog @ exclusive_latch.txt ‘test excl. parent2 l0’ 1 4 5 6 > /dev/null &
sleep 2
sqlplus /nolog @ exclusive_latch.txt ‘test excl. parent2 l0’ 1 6 7 6 > /dev/null &
wait

–//执行x2.sh
$ . x2.sh
112841
..

$ pstree -ap

  |   |   |-sqlplus,5545 \040\040\040\040\040\040 @ exclusive_latch.txt test\040excl.\040parent2\040l0 1 2 3 300
  |   |   |   |-oracle,5595 (description=(local=yes)(address=(protocol=beq)))
  |   |   |   `-sleep,5726 300

$ kill -9 5595 5545

$ grep  -v ‘^.*: $’ /tmp/peekx_112841.txt | cut -c10- | uniq -c
      1  sysdate             laddr
      1  ——————- —————-
      1  2019-04-16 11:28:42 0000000060009978
      1  statement processed.
    107  [060009978, 060009980) = 0000001b 00000000
      6  [060009978, 060009980) = 0000001c 00000000
      6  [060009978, 060009980) = 0000001e 00000000
    201  [060009978, 060009980) = 00000000 00000000

–//kill后后续的会话持有没有问题.估计pmon之类的进程会做清理工作.

(0)
上一篇 2022年3月22日
下一篇 2022年3月22日

相关推荐