数据库SQL查询表的建立教程

建学生表

create table student

         (snochar(9) primary key,

         snamechar(20) unique,

ssex char(2),

sage smallint,

sdept char(20)

);

create table course

         (cnochar(4) primary key,

         cnamechar(40) no null,

         cpnochar(4),

         ccreditsmallint,

         foreignkey (cpno) references course(cno)

         );

create table sc

         (snochar(9),

         cnochar(4),

         gradesmallint,

         primarykey(sno, cno),

         foreignkey(sno) references student(sno),

         foreignkey(cno) references course(cno)

);

insert

into student(sno,sname,ssex,sage,sdept)

values(‘201215121′,’李勇’,’男’,20,’cs’);

insert

into student (sno,sname,ssex,sage,sdept)

values (‘201215122′,’刘晨’,’女’,19,’cs’);

insert

into student (sno,sname,ssex,sage,sdept)

values (‘201215123′,’王敏’,’女’,18,’ma’);

insert

into student (sno,sname,ssex,sage,sdept)

values (‘201215125′,’张立’,’男’,19,’is’);

insert

into course(cno,cname,cpno,ccredit)

values(‘2’,’数学’,’null’,’2’);

insert

into course(cno,cname,cpno,ccredit)

values(‘6’,’数据处理’,’null’,’2’);

insert

into course(cno,cname,cpno,ccredit)

values(‘4’,’操作’,’6’,’3’);

insert

into course (cno,cname,cpno,ccredit)

values(‘7′,’pscal语言’,’6′,’4′);

insert

into course (cno,cname,cpno,ccredit)

values(‘5′,’数据结构’,’7′,’4′);

insert

into course (cno,cname,cpno,ccredit)

values(‘1′,”,’5′,’4’);

insert

into course (cno,cname,cpno,ccredit)

values(‘3′,’信息系统’,’1′,’4′);

insert

into sc(sno,cno,grade)

values(‘200215121’,’1’,’92’);

insert

into sc (sno,cno,grade)

values(‘200215121′,’2′,’85’);

insert

into sc (sno,cno,grade)

values(‘200215121′,’3′,’88’);

insert

into sc (sno,cno,grade)

values(‘200215122′,’2′,’90’);

insert

into sc (sno,cno,grade)

values(‘200215122′,’3′,’80’);

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