SQL数据库面试题以及答案（50例题）

• 生活家

数据库面试题以及答案50例题”>SQL数据库面试题以及答案（50例题）

Student(S#,Sname,Sage,Ssex)学生表
S#：学号
Sname：学生姓名
Sage：学生年龄
Ssex：学生性别
Course(C#,Cname,T#)课程表
C#：课程编号
Cname：课程名称
T#：教师编号
SC(S#,C#,score)成绩表
S#：学号
C#：课程编号
score：成绩
Teacher(T#,Tname)教师表
T#：教师编号：
Tname：教师名字

问题：

1、查询“001”课程比“002”课程成绩高的所有学生的学号

select a.S# from (select S#,score from SC where C#='001')a, (select s#,score from SC where c#='002')b Where a.score>b.score and a.s# = b.s#;

2、查询平均成绩大于60分的同学的学号和平均成绩

select S#, avg(score) from sc group by S# having avg(score)>60

3、查询所有同学的学号、姓名、选课数、总成绩

select student.S#, student.Sname, count(sc.C#), sum(score) from student left outer join SC on student.S# = SC.S# group by Student.S#, Sname

4、查询姓‘李’的老师的个数：

select count(distinct(Tname)) 
from teacher 
where tname like '李%';

5、查询没有学过“叶平”老师可的同学的学号、姓名：

select student.S#, student.Sname 
from Student 
where S# not in (select distinct(SC.S#) from SC,Course,Teacher 
where sc.c#=course.c# AND teacher.T#=course.T# AND Teahcer.Tname ='叶平');

6、查询学过“叶平”老师所教的所有课的同学的学号、姓名：

select S#,Sname   from Student    
where S# in (select S# from SC ,Course ,Teacher 
where SC.C#=Course.C# and Teacher.T#=Course.T# 
and Teacher.Tname='叶平' group by S# 
having count(SC.C#)=(select count(C#) from Course,Teacher  
where Teacher.T#=Course.T# and Tname='叶平'));

7、查询学过“011”并且也学过编号“002”课程的同学的学号、姓名：

select Student.S#,Student.Sname 
from Student,SC where Student.S#=SC.S# 
and SC.C#='001'and 
exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='002');

8、查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名：

Select S#,Sname 
from (select Student.S#,Student.Sname,score ,
(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2    
from Student,SC 
where Student.S#=SC.S# and C#='001') S_2 
where score2 < score;

9、查询所有课程成绩小于60的同学的学号、姓名：

select S#, sname 
from student 
where s# not in 
(select student.s# from student, sc where s.s# = sc.s# and score>60);

10、查询没有学全所有课的同学的学号、姓名：

select student.s#, student.sname 
from student, sc
where student.s#=sc.s# 
group by student.s#, student.sname 
having count(c#)<(select count(c#) from course);

11、查询至少有一门课与学号为“1001”同学所学相同的同学的学号和姓名：

select s#, Sname 
from Student, SC 
where student.s# = sc.s# 
and c# in (select c# from SC where s#='1001');

12、查询至少学过学号为“001”同学所有一门课的其他同学学号和姓名；

select distinct sc.s# , sname 
from student, sc 
where student.s#=sc.s# 
and c# in (select C# from sc where s#='001');

13、把“SC”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩：

Update Sc Set Score=(Select Avg(s2_Score) From sc s2 Where s2.c#=sc.c#)  
Where c# IN
(Select c# From sc cs INNER JOIN Teacher tc ON cs.t#=tc.t# WHERE tname ='叶平')

14、查询和“1002”号的同学学习的课程完全相同的其他同学学号和姓名：

select s# from sc where c#  in 
(select c# from sc where s#='1002') 
group by s# having count(*)=
(select count(*) from sc where s#='1002');

15、删除学习“叶平”老师课的SC表记录：

delect sc 
from course, Teacher 
where course.c#=sc.c# 
and course.t#=teacher.t# 
and tname='叶平';

16、向SC表中插入一些记录，这些记录要求符合以下条件：没有上过编号“003”课程的同学学号、002号课的平均成绩：

Insert SC select S#,'002',
(Select avg(score) from SC where C#='002') 
from Student where S# not in (Select S# from SC where C#='002');

17、按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”三门的课程成绩，按如下形式显示：学生ID，数据库，企业管理，英语，有效课程数，有效平均分：

select s# as 学生ID,
(select score from sc where sc.s#=t.s# and c#='004') as 数据库,
(select score from sc where sc.s#=t.s# and c#='001') as 企业管理,
(select score from sc where sc.s#=t.s# and c#='006') as 英语,
count(*) as 有效课程数, avg(t.score) as 平局成绩
from sc as t
group by s# 
order by avg(t.score)

18、查询各科成绩最高和最低的分： 以如下的形式显示：课程ID，最高分，最低分

select L.c# as 课程ID, L.score as 最高分,
R.score as 最低分
from sc L, sc R 
where L.c# = R.c# 
and L.score = (select max(IL.score) 
        from sc IL, student as IM 
        where L.c#=IL.c# and IM.s#=IL.s#
        group by IL.c#)
and R.score = (select min(IR.score)
        from sc as IR
        where R.c#=IR.c#
        group by IR.c#);

19、按各科平均成绩从低到高和及格率的百分数从高到低顺序：

SELECT t.C# AS 课程号,
max(course.Cname)AS 课程名,
isnull(AVG(score),0) AS 平均成绩,
100 * SUM(CASE WHEN  isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分数     
FROM SC T,Course     
where t.C#=course.C#     
GROUP BY t.C#      
ORDER BY 100 * SUM(CASE WHEN  isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC

20、查询如下课程平均成绩和及格率的百分数(用”1行”显示): 企业管理（001），马克思（002），OO&UML （003），数据库（004）：

21、查询不同老师所教不同课程平均分从高到低显示：

 SELECT max(Z.T#) AS 教师ID,
 MAX(Z.Tname) AS 教师姓名,
 C.C# AS 课程ID,
 AVG(Score) AS 平均成绩     
 FROM SC AS T,Course AS C ,Teacher AS Z    
 where T.C#=C.C# and C.T#=Z.T#   
 GROUP BY C.C#    
 ORDER BY AVG(Score) DESC

22、查询如下课程成绩第3名到第6名的学生成绩单：企业管理(001)，马克思(002)，UML(003)，数据库(004)：

23、统计下列各科成绩，各分数段人数：课程ID，课程名称，[100-85],[85-70],[70-60],[ 小于60] ：

SELECT SC.C# as 课程ID, Cname as 课程名称,
SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 - 85]  ,
SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 - 70],
SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 - 60],
SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -]     
FROM SC,Course     
where SC.C#=Course.C#     
GROUP BY SC.C#,Cname;

24、查询学生平均成绩及其名次：

SELECT 1+(SELECT COUNT( distinct 平均成绩)                
FROM (SELECT S#,AVG(score) AS 平均成绩                       
FROM SC                   
GROUP BY S#  ) AS T1  WHERE 平均成绩 > T2.平均成绩) as 名次,       
S# as 学生学号,平均成绩      
FROM (SELECT S#,AVG(score) 平均成绩             
FROM SC         
GROUP BY S# ) AS T2      
ORDER BY 平均成绩 desc;

25、查询各科成绩前三名的记录（不考虑成绩并列情况）：

SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数       
FROM SC t1        
WHERE score IN 
(SELECT TOP 3 score               
FROM SC               
WHERE t1.C#= C#             
ORDER BY score DESC)

26、查询每门课程被选修的学生数：

select c#, count(s#) 
from sc 
group by c#;

27、查询出只选修一门课程的全部学生的学号和姓名：

select sc.s#, student.sname, count(c#) as 选课数
from sc,student 
where sc.s# =student.s# 
group by sc.s#,Student.sname 
having count(c#)=1;

28、查询男生、女生人数：

select count(Ssex) as 男生人数 
from student 
group by Ssex 
having Ssex='男'；
select count(Ssex) as 女生人数 
from student 
group by Ssex 
having Ssex='女';

29、查询姓“张”的学生名单：

select sname 
from student 
where sname like '张%';

30、查询同名同姓的学生名单，并统计同名人数：

select sanme,count(*) 
from student 
group by sname 
havang count(*)>1;

31、1981年出生的学生名单（注：student表中sage列的类型是datetime）:

select sname, convert(char(11),DATEPART(year,sage)) as age
from student 
where convert(char(11),DATEPART(year,Sage))='1981';

32、查询平均成绩大于85的所有学生的学号、姓名和平均成绩：

select Sname,SC.S# ,avg(score)     
from Student,SC      
where Student.S#=SC.S# 
group by SC.S#,Sname 
having    avg(score)>85;

33、查询每门课程的平均成绩，结果按平均成绩升序排序，平均成绩相同时，按课程号降序排列：

select C#, avg(score) 
from sc 
group by c# 
order by avg(score), c# desc;

34、查询课程名称为“数据库”，且分数低于60的学生名字和分数：

select sname, isnull(score,0) 
from student, sc ,course 
where sc.s#=student.s#  and sc.c#=course.c# and course.cname='数据库' and score<60;

35、查询所有学生的选课情况：

select sc.s#,sc.c#,sname,cname 
from sc,student course 
where sc.s#=student.s# and sc.c#=course.c#;

36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数：

select distinct student.s#,student.sname,sc.c#,sc.score 
from student,sc 
where sc.score>=70 and sc.s#=student.s#;

37、查询不及格的课程，并按课程号从大到小的排列：

select c# 
from sc 
where score<60 
order by c#;

38、查询课程编号为“003”且课程成绩在80分以上的学生的学号和姓名：

select sc.s#,student.sname 
from sc,student 
where sc.s#=student.s# and score>80 and c#='003';

39、求选了课程的学生人数：

select count(*) from sc;

40、查询选修“叶平”老师所授课程的学生中，成绩最高的学生姓名及其成绩：

select student.sname,score 
from student,sc,course c, teacher 
where student.s#=sc.S# and sc.c#=c.c#
and c.T#=teacher.T#
and teacher.tname='叶平' 
and sc.score=(select max(score) from sc where c#=c.c#);

41、查询各个课程及相应的选修人数：

select count(*) from sc group by c#;

42、查询不同课程成绩相同的学生和学号、课程号、学生成绩：

select distinct a.s#,b.score 
from sc a ,sc b 
where a.score=b.score 
and a.c#<>b.c#;

43、查询每门课程成绩最好的前两名：

select t1.s# as 学生ID,t1.c#  课程ID, Score as 分数
from sc t1 
where score in (select top 2 score from sc 
        where t1.c#=c#
        order by score desc)
order by t1.c#;

44、统计每门课程的学生选修人数(超过10人的课程才统计)。要求输出课程号和选修人数，查询结果按人数降序排序，若人数相同，按课程号升序排序：

select c# as 课程号,count(*) as 人数
from sc 
group by c#
order by count(*) desc c#;

45、检索至少选修两门课程的学生学号：

select s# 
from sc 
group by s# 
having count(*)>=2;

46、查询全部学生选修的课程和课程号和课程名：

select c# ,cname
from course 
where c# in (select c# from sc group by c#);

47、查询没学过”叶平”老师讲授的任一门课程的学生姓名：

select sname 
from student 
where s# not in (select s# from course,teacher,sc where course.t#=teacher.t# and sc.c#=course.c# 
and tname='叶平');

48、查询两门以上不及格课程的同学的学号以及其平均成绩：

select s#,avg(isnull(score,0)) 
from sc 
where s# in (select s# from sc where score<60 group by s# having count(*)>2)
group by s#;

49、检索“004”课程分数小于60，按分数降序排列的同学学号：

select s# 
from sc 
where c#='004' 
and score<60 
order by score desc;

50、删除“002”同学的“001”课程的成绩：

delect from sc 
where s#='002' 
and c#='001';
赞 (0)
上一篇 2022年3月21日
下一篇 2022年3月21日

相关推荐