以查询前20到30条为例,主键名为id
方法一: 先正查,再反查
select top 10 * from (select top 30 * from tablename order by id asc) a order by id desc
方法二: 使用left join
select top 10 a.* from tablename a
left outer join (select top 20 * from tablename order by id asc) b
on a.id = b.id
where b.id is null
order by a.id asc
方法三: 使用not exists
select top 10 * from tablename a
where id not exists
(select top 20 * from tablename b on a.id = b.id)
方法四: 使用not in
select top 10 * from tablename
where id not in
(select top 20 id from tablename order by id asc)
order by id asc
方法五: 使用rank()
select id from
(select rank() over(order by id asc) rk, id from tablename) t
where rk between 20 and 30
中第五种方法看上去好像没有问题,查了下文档,当over()用于rank/row_number时,整型列不能描述一个列,所以会产生非预期的效果. 待考虑下,有什么办法可以修改为想要的结果.